Moment of inertia:

$\overline{){\mathbf{I}}{\mathbf{=}}{\mathbf{m}}{{\mathbf{r}}}^{{\mathbf{2}}}}$

I is proportional to mr^{2}

Mass of a sphere:

$\begin{array}{rcl}\mathbf{m}& \mathbf{=}& \mathbf{V}\mathbf{\rho}\\ & \mathbf{=}& \frac{\mathbf{4}}{\mathbf{3}}{\mathbf{\pi r}}^{\mathbf{3}}\mathbf{\rho}\end{array}$

You have two steel solid spheres. Sphere 2 has twice the radius of sphere 1.

By what factor does the moment of inertia I_{2} of sphere 2 exceed the moment of inertia I_{1} of sphere 1?

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